Name This Error

Anon

What does Too Few Arugments mean? Also so your saying that I just cannot have an " like in <a href="blank.php"> I cannot have the " so it would be <a href='blank.php'>??? Would that be it? So back to my error I am getting this error:
Warning: printf(): too few arguments in c:\program files\apache group\apache\htdocs\saintparis\classout.php on line 22

What does that mean?

Chad

Anon

your first question is yes you can do a <a href='blank.php'> or another way is by backslashing the " <a href=\"blank.php\">

and your second one. the printf function needs two arguments if you are printing a string or number or whatever, goto the php site and look at the printf() function it is a good help, but lets say you wanted to print a string $blah. well to print that with printf() you would do this printf("%s is blah",$blah); you see the first argument is how you want to format the text and the second one is the variable that is in %s place. you can also have multiple variables and multiple %s by separating them with commas.

Anon

Well here is my code. Can you help make it work?
<?php
$db = mysql_connect("localhost");
mysql_select_db("saintparis", $db);
$sql = "select * from class where class_type='$classtype1'";
$result = mysql_query($sql);
while ($row = mysql_fetch_array($result)) {
printf("<tr><td width='98%' valign='top' height='19'><a href='classfinalout.php?name=%s'>%s</a></td></tr>\n",$row["class_name"],$row["class_name"]);
}
?>

$clastype1 is coming from a previous page. It works so don't worry bout that. Whats wrong with that code? Thanks!
Chad

ziong

it should be :
printf("<tr><td width='98%%' valign='top' height='19'><a href='classfinalout.php?name=%s'>%s</a></td></tr>\n",$row["class_name"],$row["class_name"]);

Since '%' is an escape character, if u want to display a '%', you should use '%%'.

Anon

It works! OH MY! Thank you soo much. I am so grateful. I am still looking at getting the date thing figured out. So any help get me on my other thread. Thank you!
Chad