passing php variable to javascripts

Anon

Hi
I came across a proble which seems to simple problem but it is difficult for me. The problem

I have a javscript code to generate the graph and I wanted to replace the code with php code . The simplified part i have printed here

chart1.addEntry("SPD", 298);

This jave script line I wanted to replace with php variable so that i can extract the value from the database and put it there in place of spd and 298 but when I extract the variable and put in in the table it does not work

The code I have used is

chart1.addEntry(<? print("mysql_result($result,0,0)");?>,<? print(mysql_result, 0,1); ?>);

Does anybody know what may be the solution to my problem. NOtethat
chart1.addEntry("SPD", 298); is written within the java scripts tag

Anon

Yes, learn how to get information out of your database. then assign it to a standard variable. then print it in the place where you are trying to print it.

look here to do the first part:

http://www.hvt-automation.nl/yapf/faq.php?cmd=viewitem&itemid=81

Anon

I know how to get it from the database. But i am sure passing variable from php to java scripts is not like how u pass the variable ot php or from php to html. I have tried all the possible option and its not as easy as you might be telling. I have been trying this for a long time. Can u try and give a example , in stead of just replying for the sake of reply

Anon

I don't reply 'for the sake of replying'. I was trying to be helpful.

You are confusing the fact that PHP is server side and javascript is client side. Hence, in order to get a php variable into javascript, you just print the variable into a place where the javascript can find it - like in the script itself.

do whatever you want to get you variable out of your database. then in the appropriate area do something like:

<?
//make your DB variable look like this
$var1="SPD";
$var2=298;

//then print this in the appropriate place
print ("chart1.addEntry(\"$var1\",$var2)");

when you are finished, check your source and see that the source has printed properly. If not, then adjust your print statement so that it looks as required.

I hope that was more helpful.

Anon

Sorry, Thanks for your kind suggestion. Thanks a lot for your help. PLEASE DO NOT TAKE IT NEGATIVELY; I misunderstood your previous post. Sorry for that

regards
raj