dereferencing returned array

[Anon]

Hi,

I've probably missed the really obvious here, but ...

I have a nifty little function that returns an array and the first element of the array indicates failure or some success status.  In the vast majority of the cases, that first value is all I need.  What I'd like to do is:

if (myFunc($arg1, $arg2)[0]>=0) {
// hoorah! it works. You get the idea
}

but PHP is not overly enamored of my [0] proposal. My question is, how do I extract the nth element of a returned array in place to avoid the two lines (of assignment; test) I'm currently using to do this?

[Anon]

how about just using parenthesis different?

if ((myFunc($arg1, $arg2))[0]>=0) {
// hoorah! it works. You get the idea
}

[van__]

Don't have much time to play with it,
but this gave me a positive test...

<?

function myFunc($var1,$var2) {
return array('true','false');
}

if ($array[array_keys(myFunc('',''))][0]>=0) {
echo "tested positive";
} else {
echo "no go";
}

?>

[van__]

...actually, that call to array_keys() is probably completeley unnecessary, but hey... it shows how it could be expanded.

[Anon]

I couldn't get Craig's idea to work (of surrounding the returned array with parens in order to dereference it).
And I didn't quite get Van's idea, but it gave me one that works nicely: I can use array_shift() since I am generally only interested in the first element of the returned array.