the if statement isn't working right!

[fahhem]

The manual says I am right but my server doesn't agree. Could someone help?

if ($password=="") {
/40/print "</font><font size='6' color='black'>"
/41/}else{?>
<br>Your username/password combination is incorrect.</font>
<br>
<form action='http://fahhem.t35.com/signin.php' method='POST'>
<table align=center width=78 cellpadding=4 cellspacing=0>
<input type='hidden' name='logsent' value='sent'><tr>
<td width="78"><font color="#FFFFFF"><b>Username</b></font></td>
<td width="92">
<input type='text' name='user' size=12 maxlength=20 onFocus='this.select()'></td></tr><tr>
<td width="78"><font color="#FFFFFF"><b>Password</b></font></td>
<td width="92"><input type='password' name='password' size=12 maxlength=20></td></tr><tr>
<td align=center colspan=2 bgcolor='#000000' width="178">
<input type='submit' value='Log In'></td></tr></table></form>
<?php }

Thanks in advance!

[Anon]

Looking at your code, it appears as though you want the following to happen.

if $password = ""
then display an empty string

if $password is anything but an empty string,
display "Your username/password combination is incorrect"

and then display the login form. Is this the desired behavior?

The only error I see is that you need a semicolon after print ""

[fahhem]

it gives me an error after the else. I want if user == "" then user is wrong. if user != "" then checkpassword and if the password given and the corect password correspond, then go to another page, other wise, put the login form. But, I can't put the login form because when I put else:?>
login form
<?php

it gives me an error on the else:?> line.

[Anon]

Your logic is incorrect, should be something like this.

if ($password == "") {
echo "Password Wrong!;
} else {
check password
if ($password == "password") {
do something
}
}

also, I don't understand your else:?>
what is the colon for?

[Anon]

oops left a double quote out of the second line.