php4 safe_mode

[rohitkaul_2000]

Hi Friends,
It's something about the safe mode behaviour of php.
We are running our php4 with "safe_mode=on" in php.ini.
According to php documentation we can't have components in the path to the executable when using functions like exec() and
system().
e.g., I can run this in php4 with safe_mode=on.
#######################################
<?
$lines=array();
$errco=0;
$cmd1="ls";
$result = exec("ls -lrt",$lines,$errco);
?>
#######################################

but when I write the below script it doesn't work:

#######################################
<?
$lines=array();
$errco=0;
$cmd1="ls -lrt * 2>&1";
$result = exec("ls -lrt",$lines,$errco);
?>
#######################################

My question is, is there a way to circumvent this problem in php4 keeping safe_mode=on.
Any help would be appreciated.
Thanks,
\Rohit

[[deleted]]

Are you sure you posted the right snippets? you don't use the $cmd1 in either script...

[rohitkaul_2000]

Oops...!!
Sorry abt that Vincent...!!!
But point being it doesn't really matter because $cmd1 variable has the same values what I want to pass to the exec() function..

Worried,
\Rohit

vincent wrote:

Are you sure you posted the right snippets? you don't use the $cmd1 in either script...

[rohitkaul_2000]

Must have been in a trance or something while writing this...
My apologies to Vincent and fellow Phpian's
code should have been like this:

e.g., I can run this in php4 with safe_mode=on.
#######################################
$lines=array();
$errco=0;
$cmd1="ls";
$result = exec($cmd1,$lines,$errco);
?>
#######################################

but when I write the below script it doesn't work:

#######################################
$lines=array();
$errco=0;
$cmd1="ls -lrt * 2>&1";
$result = exec($cmd1,$lines,$errco);
?>
#######################################

My question is, is there a way to circumvent this problem in php4 keeping safe_mode=on.
Any help would be appreciated.
Thanks,
\Rohit