Date problem

Anon

I have a form with 3 dropdown date field(day,month,year)where people select their date of birth.

I am taking the $date, $month,and $year and turning into timestamp like:

$age = mktime($hours, $minutes, $seconds, $month, $day, $year);

its works fine,, but problem is when the year is before 1970.. the number generated by mktime is negative..why????

please pelase help..

thankz in advance

buck2bcr

"The mktime function returns a timestamp for a given date, the number of seconds since January 1, 1970."

"All the time functions work off hte UNIX epoch, which is January 1, 1970."

Got this from core php programming book.

Buck

Anon

php.net is a great source of info:

Returns the Unix timestamp corresponding to the arguments given. This timestamp is a long integer containing the number of seconds between the Unix Epoch (January 1 1970) and the time specified.

nageshyd

<?
function dow($dd,$mm,$yy)
{
$res=($yy+(int)($yy-1)/4-(int)($yy-1)/100+(int)($yy-1)/400+julianday($dd,$mm,$yy))%7;
if($res==1)
$res="Sunday";
elseif($res==2)
$res="Monday";
elseif($res==3)
$res="Tuesday";
elseif($res==4)
$res="Wednesday";
elseif($res==5)
$res="Thursday";
elseif($res==6)
$res="Friday";
else
$res="Saturday";
return($res);
}
function julianday($dd,$mm,$yy)
{
$days=array(31,0,31,30,31,30,31,31,30,31,30,31);
$days[1]=$yy%4==0&&$yy%100!=0||$yy%400==0?29:28;
for ($i=1;$i<$mm;$i++)
$jd=$jd+$days[$i-1];
return($jd+$dd);
}
function age($dd,$mm,$yy)
{
$now=split("-",date("d-m-Y"));
$dd1=$now[0];
$mm1=$now[1];
$yy1=$now[2];
if($yy1==$yy)
{
$age["years"]=0;
$age["days"]=julianday($dd1,$mm1,$yy1)-julianday($dd,$mm,$yy);
return($age);
}
else
{
$ans1=$yy%4==0&&$yy%100!=0||$yy%400==0?366-julianday($dd,$mm,$yy):365-julianday($dd,$mm,$yy);
$ans2=julianday($dd1,$mm1,$yy1);
$sy=$yy+1;
$ly=$yy1-1;
while($sy++<=$ly)
$sum=$sy%4==0&&$sy%100!=0||$sy%400==0?$sum+366:$sum+365;
}
$years=(float)($sum+$ans1+$ans2)/365;
$days=($years-(int)($years))*365;
$age[years]=(int)$years;
$age[days]=(int)$days;
return ($age);
}
?>
<head><title>Date functions</title></head><body><TABLE><FORM method=post><TR><Td>Enter Date</Th><TD><INPUT name=dob></TD></TR> <TR><Th><INPUT type=submit></Th></TR></FORM></TABLE></body>

<?
if($dob)
{
$dob=str_replace(" ","",$dob);
if(!ereg("^{[0-9]{1,2}(-|/)[0-9]{1,2}(-|/)[0-9]{4}$",$dob))}
$msg="Invalid date";
elseif(ereg("^{[0-9]{1,2}/[0-9]{1,2}/[0-9]{4}",$dob))}
$dob=split("/",$dob);
else
$dob=split("-",$dob);
if($msg) die($msg);
$dd=$dob[0];
$mm=$dob[1];
$yy=$dob[2];
$age=age($dd,$mm,$yy);
echo "The date you entered is <b>$dd-$mm-$yy</b><br>";
echo "The weekday is <B>" . dow($dd,$mm,$yy) . "</b><br>";
echo "Date difference or age is <B>$age[years] years and $age[days] days </b><br>";
}
?>