i have this code in my page:
<?php
echo "<title>Prijava Administratora</title>";
echo "<body bgcolor=#000000 text=#ffffff link=#cccccc vlink=#cccccc alink=#cccccc>";
require ('konfiguracija.php');
$baza = mysql_connect("$adresabaze","$userbaze","$sifrabaze");
mysql_select_db("$bazapodataka",$baza);
$rezultat = mysql_query("SELECT * FROM admin",$baza);
while ($red = mysql_fetch_array($rezultat)) {
if($admininistrator==$red["admin_ime"] && ($administratorsifra==$red["admin_sifra"]))
{
setcookie("korisnik", "glavni");
echo "<p align=center>Uspjesno ste prijavljeni, prosljedjivanje je u toku!<br>Ukoliko ne budete proslijedjeni za nekoliko sekundi, kliknite <a href=\"administrator.php\">ovdje</a>.</p>";
} else {
echo "<p align=center>Pogresno korisnicko ime ili sifra! Kliknite <a href=\"logovanje.php\">ovdje</a> da pokusate ponovo!</p>";
}
}
?>
and i get this error every time i try to load that page:
Warning: Supplied argument is not a valid MySQL result resource in c:\program files\apache group\apache\wwwroot\novosti\prijava.php on line 8
and line 8 is this:
while ($red = mysql_fetch_array($rezultat)) {
can anyone help me fix the problem?