Certain images from result!

[Anon]

Can anyone tell me how I can show certain images depending on what are in different fields within the database!

Set-up: Six fields with information, I want the ones with information to show certain images and ones without information to be ignored!?

HELP?

Thnx
Daniel

[bastien]

<?
if ($result=="") {
echo "no Image available";
}else{
echo "<img src=\"/mynakedgirlfriend.gif\">";
}

just check for a blank value when the dataset is returned. If there is no data then display nothing or if there is a value for the result then show an image...

hth

bastien

[Anon]

Is there a way of checking three blank values all at the same time within a string.

I have atempted it with this and got errors!

if ($myrow['realvideolow'] $myrow['realvideolow'] $myrow['realvideolow']=="") {
echo "";
}else{
echo "<a href=# onclick=videopopup=openIT('video_real.php?stream=".$myrow['realvideolow']."',400,400,null,null,'mywin001');><img src=assests/gfx/video-low.gif width=75 height=25 border=0></a>";
}