Greetings!
I have one minor question, but I don't know, how to make it go thru...
What is what I want o actually do is t put the entire source of the file into one variable, something like:
$variable=readfile("/path/file.txt"), but that's a FAR way from that it could work, as openfile opens the file WITHOUT sending it to variable...
I wish for something like
$variable=readfile("/path/file.txt");
mysql_query="insert int database '$var1', '$var2', '$var3', '$variable');
Is there anyway to actually DO that?
Please help.
Best regards.
zer0Kode, Linux developer.
