Value of Select Box

[Anon]

I have a select box that the user can change the value of:

$year=date("Y");
$years = array(1996,1997,1998,1999,2000,2001,2002);
echo "<SELECT name=goyear>";
for($y=0; $y<8; $y++)
{
if ($year==$years[$y])
{
echo $sel = ' selected';
}
else
{
$sel = '';
}
echo '<option value="'.$years[$y].'"'.$sel.'>'.$years[$y].'</option>';
}
echo "</SELECT>";

How do I capture what the value is if the user changes it?

For example: I have a query that returns results based on a default year. However, when the user selects a different date and selects a GO button I will requery the db for the appropriate results.

Struggling with how to capture the current value in the select box...

Appreciate the insight!!

[Anon]

when you submit the form, the value of the select will be stored in a variable with the name of your select item, in your case, it will be stored in $goyear

[Anon]

I understand how that would work...but this it appears that I may not be doing something correctly?

You see I am originally defaulting the value into the select box. Then when I try to assign the current value of goyear ($yr = $goyear) where goyear is the select box, I get a NULL value returned....?

//DEFAULTS YEAR TO CURRENT YEAR
$year=date("Y");
$years = array(1996,1997,1998,1999,2000,2001,2002);
echo "<SELECT name=goyear>";
for($y=0; $y<8; $y++)
{
if ($year==$years[$y])
{
echo $sel = ' selected';
}
else
{
$sel = '';
}
echo '<option value="'.$years[$y].'"'.$sel.'>'.$years[$y].'</option>';
}
echo "</SELECT>";
$yr = $goyear;

I am actually using 3 separate drop downs and will ultimately concatenate all of them together and use the value within a select query to start the page off on today's date. Problem is I cannot get the default value of the select assigned......

Any insight?

Thanks in advance....