parse error, expecting `T_STRING'

[Anon]

I am getting this parse erro on a asp2php coverted code section, I'm no php expert, can anyone tell me whats wrong with this code. Thanks. Line 39 is remarked.

Parse error: parse error, expecting T_STRING' orT_VARIABLE' or `T_NUM_STRING' in /var/www/html/search.php on line 39

<b>Brand:<b>
<?php
echo "<select name=\"brand\">";
$db = mysql_connect("localhost", "user", "password");
mysql_select_db("database",$db);
$result = mysql_query("SELECT DISTINCT Brand FROM table WHERE CategoryID = $gotcategory ",$db);
if ($myrow = mysql_fetch_array($result)) {
do {
echo "<option value=\"$myrow['brand']\">$myrow['brand']</option>\n"; // line 39
} while ($myrow = mysql_fetch_array($result));
} else {
echo "Sorry, no records were found!";
}
echo "</select>";
?>

[Anon]

From what I can gather (anyone correct me if I'm wrong), PHP will let you concatenate strings and variables directly, ie echo "your name is $name", or "this is item # $row[$i]", but it won't work with arrays where the index is a string, like $row['index'] (even if you're careful with the double/single quotes). So instead of writing $myrow['brand'], take the number of the column, or concatenate the strings manually, ie: echo "<option value='" . $myrow['brand'] . "'>" . myrow['brand'] . "</option>\n";

[Anon]

I found a better way, without using the concatenation with . nor using the column number instead of column name. Just add {} around the array variable, like this:
echo "<option value='{$myrow['brand']}'>{$myrow['brand']}</option>\n"

🙂

[akpark]

Hello,

I had the similiar problem, but I found the answer from the net.

Basically, what it's saying is that you do not need " or ' for your array.

See http://bellarmine.lmu.edu/technology/notes/PHP_troubleshooting_tips.htm for more information.