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[Anon]

Hi.

Can anyone tell what I am doing wrong if i get this error message?
Supplied argument is not a valid MySQL result resource ..

My code looks like this:
printf(mysql_result($result,0,\"firstname\"));
(where firstname is the fieldname in the DB.)

Thanks! :-)

[Anon]

Hallo Elisa!!!

Such type of error may happen dueto connection problem to the server, DB, or some other errors like wrong table name, using unknown variables.....

If you have time, visite this site:
http://www.php.net/manual/en/function.mysql-result.php

Can you post your query?

Solomon