I'm a moron

[Anon]

I know that I am a moron, but what is wrong with this. I get a Supplied argument is not a valid MySQL result resource error messsage. By the way the value of $i6token[uid] is 003.

$q2 = \"select type from user where id = $i6token[uid]\";
$result2 = mysql_query($q2,$i6link);
while($row2 = mysql_fetch_array($result2))
{
echo$row2[\"type\"];
}

Thanks in advance for your help.

[kris81]

if you want to debug this you should try to add something like this:

$q2 = \"select type from user where id =

IF (!$Q2) ECHO "ERROR";

$i6token[uid]\";
$result2 = mysql_query($q2,$i6link);

IF (!$RESULT2) ECHO "ERROR";

while($row2 = mysql_fetch_array($result2))
{
echo$row2[\"type\"];
}

This will give you an idea where your mistake took place

[Anon]

thanks, that did it

[Anon]

$q2 = "select type from user where id = $i6token[uid]";
$result2 = mysql_query($q2);
while($row2 = mysql_fetch_array($result2))
{
printf("%s",$row2['type']);
}