Hello geniuses.
I have compiled gd1.8 I have made a make install
I have upadted ld.so.conf with /usr/lib and even /usr/local/lib since my gd is in /usr/local/
I have ran ldconf
When I compile php with :
./configure --with-apxs=/usr/local/apache/bin/apxs --with-mysql=/usr/local/current/ --with-zlib --with-gd=/usr/local --with-jpeg-dir=/usr/local --enable-url-includes --enable-track-vars --with-xml --enable-sysvsem=yes --enable-sysvshm=yes --with-ftp --with-calender --with-exif
I get inthe configure the following which ales me:
checking for libjpeg (needed by gd-1.8+)... yes
checking for jpeg_read_header in -ljpeg... yes
checking for gdImageCreateFromJpeg in -lgd... no
it seems it find the jpeh library and the headers and what does the no entry mean ?
because something does not work when i call the script I wish to run it returns:
Warning: Supplied argument is not a valid Image resource in /usr/local/htdoc/simplyfree/autogallery/functions.inc on line 177
Warning: ImageJpeg: No JPG support in this PHP build in /usr/local/htdoc/simplyfree/autogallery/functions.inc on line 178
I have read throught he threads here but I did not seem to find my error. Well it is 3 am here and the admin is pushy, thx for any help.
Night
Ps libjpeg.so is in /usr/lib AND /usr/local/lib the h file is in /usr/include and /usr/local/include
