Using Apache, PHP LOCALLY on Win98

[Anon]

Hi, i have php working while using apache, i was just wondering if anyone knew how to be able to run an include(), or require() function to another php script locally (while passing parameters).

for example, i've tried
<?php require("http://127.0.0.1/header.php"); ?>

and it generates the error

Fatal error: Failed opening required 'http://127.0.0.1/header.php' (include_path='') in C:_cslug\public_html/index.php on line 18

though you might ask why i don't just do <?php require("header.php"); ?>, the reason is because i wish to eventually be able to pass parameters like the following
<?php require("http://127.0.0.1/header.php?header=main"); ?>

i have the exact same scripts working on another domain, but just can't get it to work locally.

any suggestions would be most helpful

P.S. Versions Apache1.3.14, PHP4.0.3pl1 on Win98SE

phoe

[Anon]

you do not need the absolute reference, ie if header.php is in the same directory as you script just <? require("header.php?this=that");?> is fine , the values will still be passed along via the url regardless.

You can however alter the include path in your PHP.ini , just open it up and search for the include_path value.

again I see no reason to though

[Anon]

I have found that I have to use actual paths like this:
C:\apache\htdocs\
I hope that this helps