Cookies to genarate images!!!!!!

Anon

HELP i whany to genarate an image using Cookies the code is as follows:

if (isset ($HTTP_COOKIE_VARS['businessoptions']))
{
include("businessoptions.inc");
}
else
echo "<IMG WIDTH=466 HEIGHT=89 LOWSRC="images/trans1x1.gif" SRC="images/iclogo.gif">";

this peace of code allows by businessoptions.inc file to used if the cooke is set but if the cookie is not set i would like to place the iclogo.gif there insted the inc file is only some html which generates an image

so in short if cooke is there include businessoptions.inc else put other image there

i need help with the else stetment as this is worng

rschmitt

I'm not quite sure if this is correct, but I don't think you can use isset() to check if a certain element in an array has been set.

Rather do a check on the value of the cookie.

Hope this helps

Anon

let me explain a bit more clearly

whant happens is when a user comes to my site they can personlise it so they click the link to the personlisation page fill in the form and have an option as a bussiness user a leisure user or a meeting users the check one of these boxes then click done which takes them back to the main page with the corect banner in place ie bussines leiurse etc however if they did not whant to personlize or dont not have cookies on or it is there first tim to my site ther is the stander banner there. i can produce the banners if they have personlised the site but not the other banner.

so what i need help with is the else bit of the code as i whant to have if cookie ther have that file there if not or the have this file or picture there

hope this explans it beter

mark

ps sorry about spelling and punctuation

rschmitt

Okay, I should have researched this a bit better before replying the first time.

First, you should be setting the cookie with a command like:

setcookie("cookieName",etc,etc,etc)

So, when doing the check for the existence of the cookie, first get the value from the $HTTP_COOKIE_VARS global variable and save it to its own variable, e.g.:

$cookieName = $HTTP_COOKIE_VARS["cookieName"];

Then

if (isset($cookieName)) {
include("businessoptions.inc");
} else {
echo "<IMG WIDTH=466 HEIGHT=89 LOWSRC=/"images/trans1x1.gif/" SRC=/"images/iclogo.gif/">";
}

should work quite nicely. Remember to escape (/) your inverted commas in an echo statement. And check the syntax of your if/else statements!

Anon

Thanks very much for your help it works like a dream you help is very much apreciated when site is finished i will put a link to this site

regards

mark lapsley

rschmitt

No problem.. my invoice is in the mail!

(kidding)

Anon

just one more litle help in my form for personalization i have a section ware they can tick a check box if the check box is selected it will set a cookie then whwn you return it will be include however if two are ticked it will still only show one of the include files

the code at the moment is

<?
if (isset ($HTTP_COOKIE_VARS['weekendop']))
{
include("weekendsaversoptions.inc");
}
if (isset ($HTTP_COOKIE_VARS['athensop']))
{
include("athensoptions.inc");
}
if (isset ($HTTP_COOKIE_VARS['weekop']))
{
include("weekendoptions.inc");
}
?>

so in short so when more than one of the check boxes are clicked in will only show one of them ie if weekendsaversoptions is selected and athensoptions is selected only weekendsaversoptions.inc will show

i have tried else statements but that does not work

any ideas

thanks mark

Anon

This is something that i've been playing around with on my site.. It's a way to get which user is coming to my site.. if the user doesn't have a cookie then i create them a guest cookie till they either log in or signup...

I see in your code that you have
if (isset ($HTTP_COOKIE_VARS['weekendop']))
to check for the existance of a cookie. In my expierence you don't need the whole $HTTP_COOKIE_VARS['weekendop'] in check to see if it's a cookie... PHP automatically checks for a cookie, IF there is then it puts the varibles into a "POST" method basically..

here is sample code that i'm using on my site right now.

// a month into the future.
$co_time = time() + 86400 * 30;
// Check to see if the user has a cookie on their computer
if (!$co_Uid && !$co_Uname){

// Setting the User ID and User Name to a default "GUEST" user
$co_Uid_val = "0";
$co_Uname_val = "GUEST";
setcookie("co_Uid", $co_Uid_val, $co_time);
setcookie("co_Uname", $co_Uname_val, $co_time);

}

just a little more info for ya.. 🙂